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How many grams of magnesium sulfate (MgSO4) are dissolved in 0.965 L of a 0.0575 M solution?
Answer – 6.68 g MgSO₄
Explanation:
- Molar Mass of Magnesium = 24.31 g/mol
- Molar Mass of Sulphur = 32.07 g/mol
- Molar Mass of Oxygen = 16.00 g/mol
- Molar Mass of MgSO₄ = 24.31 + 32.07 + 4(16.00) = 120.38 g/mol
Substitute 0.0575 M = x / 0.965 L
Isolate x: 0.055488 mol MgSO₄ = x
Rewrite: x = 0.055488 mol MgSO₄
= 6.67959 g MgSO₄
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